# How do you determine the oxidation number of nitrogen in the nitrate ion?

Jun 29, 2016

The sum of the oxidation numbers equals the charge on the ion.

#### Explanation:

For $N {O}_{3}^{-}$, ${N}_{\text{Oxidation Number"+3xxO_"Oxidation number}} = - 1$.

Now $O$ normally takes an oxidation number of $- I I$ and it does so here.

Thus ${N}_{\text{Oxidation Number}} + \left(3 \times - 2\right) = - 1$.

Clearly, ${N}_{\text{Oxidation Number}} = + V$

What is the oxidation state/number of $N$ in $N O$, $N {O}_{2}$, and ${N}_{2} {O}_{4}$?