How do you determine the oxidation state of metal ions?

1 Answer
Aug 14, 2016

Answer:

Well, for #M^(2+)# and #M^(3+)# it's easy, we have #II+# and #III+# oxidation states.

Explanation:

For complex ions such as #MnO_4^-# and #Cr_2O_7^(2-)# you have to do a little more work, but most of it is routine. Oxygen, in all its oxides, assumes an oxidation state of #-II#. Thus the oxidation state of the metal in these oxides is the Group oxidation number, i.e. the maximum oxidation numbers, #Mn(VII+)#, and #Cr(VI+)#. Are you clear on how these designations were obtained?

Can you tell me the metal oxidation states in: #MnO_2#; #ZrCl_4#; #PtCl_4#; #Fe_2O_3#; #Pd(PPh_3)_4#; and #[Fe(C-=N)_6]^(3-)#?