How do you determine the solution in terms of a system of linear equations for 2x-y=3 and 3x+y=2?

Oct 23, 2015

$\left(x , y\right) = \left(1 , - 1\right)$

Explanation:

Given
[1]$\textcolor{w h i t e}{\text{XXX}} 2 x - y = 3$
[2]$\textcolor{w h i t e}{\text{XXX}} 3 x + y = 2$

[3]$\textcolor{w h i t e}{\text{XXX}} 5 x = 5$
Dividing [3] by $5$
[4]$\textcolor{w h i t e}{\text{XXX}} x = 1$
Substituting $1$ for $x$ in [2]
[5]$\textcolor{w h i t e}{\text{XXX}} 3 \cdot \left(1\right) + y = 2$
[6]$\textcolor{w h i t e}{\text{XXX}} y = - 1$