How do you determine the solution in terms of a system of linear equations for #x^2 + y^2 = 13#, #2x-3y = -6#?
Solutions may be found by substitution of the suitably rearranged first order equation (the second one in your particular system of equations) into the second order equation (the first one in your system). The quadratic will typically have two solutions for each substitution.
Taking the first equation
And rearranging to find the value of one of the variables in terms of the other, for example (it would be possible to do this in either of two ways)
This value of x may be substituted into the other equation (which is a quadratic), that is
Multiplying throughout by 4 for convenience
This is a messy equation; it would be quickest in an exam to apply the quadratic formula rather than searching for factors. So, values of y satisfying this equation are given by:
The corresponding values of
Remember to check workings, and to check consistency of solutions by substitution into the given equations.