# How do you determine whether there are two, one or no real solutions given the graph of a quadratics function does not have an x-intercept?

Sep 8, 2017

If a graph of a quadratic, $f \left(x\right)$, does not have an x-intercept
then $f \left(x\right) = 0$ has no Real solutions.

#### Explanation:

The x-axis is composed of all points for which $f \left(x\right)$ (or, if you prefer, $y$) is equal to $0$

If the graph of $f \left(x\right)$ does not have an x-intercept
then it has no (Real) points for which $f \left(x\right) = 0$

Sep 8, 2017