# How do you differentiate # -(2/(3x)) #?

##### 1 Answer

May 29, 2016

See below for two solutions.

#### Explanation:

**If you want to use the quotient rule** , you can.

# = -[((0)3x-2(3))/(3x)^2]#

# = -[(-6)/(9x^2)] = 6/(9x^2) = 2/(3x^2)#

**Alternatively** , you can **rewrite the expression** before differentiating.

Now use the power and constant multiple rules.

# = (-1)(-2/3)x^(-1-1) = 2/3x^-2 = 2/(3x^2)#

Use whichever method you like.