How do you differentiate #2xy=y^2-x#?
1 Answer
May 6, 2018
Explanation:
#"differentiate "color(blue)"implicitly with respect to x"#
#"noting that "#
#•color(white)(x)d/dx(y)=dy/dx" and "d/dx(y^2)=2ydy/dx#
#"differentiate "2xy" using the "color(blue)"product rule"#
#rArr2xdy/dx+2y=2ydy/dx-1#
#rArrdy/dx(2x-2y)=-1-2y#
#rArrdy/dx=-(1+2y)/(2x-2y)#
