Question

How do you differentiate `(3x^2 -5x )/ (2x-1)` using the quotient rule?

Answer 1

`y'=(6x^2-6x+5)/(2x-1)^2`

Explanation:

Using the Quotient rule we get
`y'=((6x-5)(2x-1)-(3x^2-5x)*2)/(2x-1)^2`
and this is

`y'=(12x^2-10x-6x+5-6x^2+10x)/(2x-1)^2`
this is

`y'=(6x^2-6x+5)/(2x-1)^2`