How do you differentiate #(4x)^3 * (2x)^6#?
1 Answer
Apr 13, 2018
Explanation:
#"differentiate using the "color(blue)"power rule"#
#•color(white)(x)d/dx(ax^n)=nax^(n-1)#
#"expanding "(4x)^3xx(2x)^6=4096x^9#
#rArrd/dx(4096x^9)=36864x^8#
