How do you differentiate #5cosx-2cosx#?
1 Answer
Aug 31, 2016
Explanation:
You may have typed this incorrectly because as it is , the expression can be simplified to one term since they are like terms.
That is
#5cosx-2cosx=3cosx#
#color(orange)"Reminder " color(red)(|bar(ul(color(white)(a/a)color(black)(d/dx(cosx)=-sinx)color(white)(a/a)|)))#
#rArrd/dx(3cosx)=-3sinx#