# How do you differentiate #5cosx-2cosx#?

##### 1 Answer

Aug 31, 2016

#### Explanation:

You may have typed this incorrectly because as it is , the expression can be simplified to one term since they are like terms.

That is

#5cosx-2cosx=3cosx#

#color(orange)"Reminder " color(red)(|bar(ul(color(white)(a/a)color(black)(d/dx(cosx)=-sinx)color(white)(a/a)|)))#

#rArrd/dx(3cosx)=-3sinx#