# How do you find the derivative of y =1/sqrt(x)?

$y = \frac{1}{\sqrt{x}} = {x}^{- \frac{1}{2}}$
$y ' = \left(- \frac{1}{2}\right) {x}^{\left(- \frac{1}{2} - 1\right)} = \left(- \frac{1}{2}\right) {x}^{\left(- \frac{1}{2} - \frac{2}{2}\right)} = \left(- \frac{1}{2} {x}^{- \frac{3}{2}}\right) = - \frac{1}{2 {x}^{\frac{3}{2}}}$