Question

How do you differentiate `A(s)=-12/s^5`?

Answer 1

`A'(s)=60/s^6`

Explanation:

This can be rewritten as

`A(s)=-12s^-5`

We can now use the power rule: `d/(ds)s^n=ns^(n-1)`. The `-12` will stay being multiplied by the variable.

`A'(s)=-12(-5)s^(-5-1)`

`A'(s)=60s^-6`

`A'(s)=60/s^6`