# How do you differentiate (e^x - e^(-x))/(e^x + e^(-x))?

${\sech}^{2} x$
The given expression is equivalent to tanh x. Its derivative is ${\sech}^{2} x$ or $\frac{1}{\cosh} ^ 2 x$.
Since cosh x = $\frac{{e}^{x} + {e}^{-} x}{2}$, the derivative can also be expressed as $\frac{4}{{e}^{2 x} + {e}^{- 2 x} + 2}$