How do you differentiate # e^x/ln x#? Calculus Differentiating Exponential Functions Differentiating Exponential Functions with Calculators 1 Answer Sasha P. Mar 15, 2016 #y'=(e^x(xlnx + 1))/(xln^2x)# Explanation: #y=f/g# #y'=(f'*g-f*g')/g^2# #y=e^x/lnx => f=e^x, g=lnx# #f'=e^x, g'=1/x# #y'=(e^xlnx - e^x/x)/ln^2x# #y'=(e^x(xlnx - 1))/(xln^2x)# Answer link Related questions How do you use a calculator to find the derivative of #f(x)=e^(x^2)# ? How do you use a calculator to find the derivative of #f(x)=e^(1-3x)# ? How do you use a calculator to find the derivative of #f(x)=e^sqrt(x)# ? What is the derivative of #e^(-x)#? What is the derivative of #ln(2x)#? How do you differentiate #(lnx)^(x)#? How do you differentiate #x^lnx#? How do you differentiate #f(x) = e^xlnx#? How do you differentiate #e^(lnx) #? How do you differentiate #y = lnx^2#? See all questions in Differentiating Exponential Functions with Calculators Impact of this question 2931 views around the world You can reuse this answer Creative Commons License