How do you differentiate #f(x)=2lnx^3#?

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Answer 1 · 2015-04-09T18:57:03

#f(x)=2lnx^3# Can be differentiated by using the chain rule
We'll go through that that after we do it the easy way.

Use the fact the #ln a^p = p lna# to rewrite the function:

#f(x)=2lnx^3=2(3lnx)=6 lnx#.

And so, #f'(x)=6*1/x=6/x#.

OR

#f(x)=2lnx^3#

#f'(x)=2[1/x^3*3x^2]=(6x^2)/x^3 = 6/x#.