Question

How do you differentiate `f(x)=(2x^2+1)(2x-1)` using the product rule?

Answer 1

`f'(x)=2(2x^2+1)+4x(2x-1)`

`=12x^2-4x+2`

Explanation:

Product rule states that `d/dx(f(x)*g(x))=f(x)*g'(x)+g(x)*f'(x)`.

Application thereof in this particular case yields

`f'(x)=2(2x^2+1)+4x(2x-1)`