How do you differentiate #f(x)=(3x^(1/2)-2)/ x# using the quotient rule?

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Answer 1 · 2016-06-27T09:02:23

#=( 4 -3 x^(1/2) )/ (2x^2) #

#((3x^(1/2)-2)/ x)^prime #

Wikipedia

#=((3x^(1/2)-2)^prime x - (3x^(1/2)-2) x^prime)/ x^2 #

#=(3/2 x^(-1/2) * x - 3x^(1/2) + 2)/ x^2 #

#=(3/2 x^(1/2) - 3x^(1/2) + 2)/ x^2 #

#=( 4 -3 x^(1/2) )/ (2x^2) #