Question

How do you differentiate `f(x)=(3x-cos^3x)^2/4` using the chain rule?

Answer 1

Yes, use the chain rule ...

Explanation:

`f'(x)=(1/4)(2)(3x-cos^3x)(3-3cos^2x)(-sinx)`

You can do some simplification:

`f'(x)=(-3/2)(3x-cos^3x)(sin^3x)`

hope that helped