How do you differentiate #f(x)=ln(sin(e^{x}))#? Calculus Basic Differentiation Rules Chain Rule 1 Answer GiĆ³ Feb 24, 2015 You can use the Chain Rule where you first derive #ln# as it is then multiply by the derivative of #sin# as it is and finally multiply by the derivative of #e#: #f'(x)=1/(sin(e^x)]*cos(e^x)*e^x=e^x*cot(e^x)# Answer link Related questions What is the Chain Rule for derivatives? How do you find the derivative of #y= 6cos(x^2)# ? How do you find the derivative of #y=6 cos(x^3+3)# ? How do you find the derivative of #y=e^(x^2)# ? How do you find the derivative of #y=ln(sin(x))# ? How do you find the derivative of #y=ln(e^x+3)# ? How do you find the derivative of #y=tan(5x)# ? How do you find the derivative of #y= (4x-x^2)^10# ? How do you find the derivative of #y= (x^2+3x+5)^(1/4)# ? How do you find the derivative of #y= ((1+x)/(1-x))^3# ? See all questions in Chain Rule Impact of this question 5641 views around the world You can reuse this answer Creative Commons License