How do you differentiate #f(x)=ln(x^x)#?

1 Answer
Nov 14, 2015

Use logarithm rules to rewrite, then use the Product Rule.

Explanation:

Remember that #log(a^b)=blog(a)#. You can use this identity to rewrite #ln(x^x)# as #xln(x)#.

Now, in order to find #d/(dx)[xln(x)]#, we must use the Product Rule.
The rule dictates that #f'(x)=color(red)(d/(dx)[x])*ln(x)+x*color(blue)(d/(dx)[ln(x)]#
Let's take a moment to determine the derivatives.
#color(red)(d/(dx)[x]=1),color(blue)(d/(dx)[ln(x)]=1/x#

Plug back in.
#f'(x)=color(red)(1)*ln(x)+x*color(blue)(1/x)#
#color(green)(f'(x)=ln(x)+1#