Question

How do you differentiate `f(x)=ln2^x-2lnx`?

Answer 1

`ln2-2/x`

Explanation:

`f'(x)=d/dxstackrel"= x(ln2)"overbrace([ln2^x])-d/dx[2lnx]`

Remember that `ln2` is just a constant and that `d/dx[lnx]=1/x`.

`f'(x)=ln2-2(1/x)=color(blue)(ln2-2/x`