How do you differentiate #f(x)=sin(4x^2) # using the chain rule? Calculus Basic Differentiation Rules Chain Rule 1 Answer Jim G. Jan 9, 2016 # 8xcos(4x^2 ) # Explanation: using the chain rule gives : # f'(x) = cos(4x^2). d/dx (4x^2 ) = cos(4x^2)(8x ) # # rArr f'(x) = 8xcos(4x^2 ) # Answer link Related questions What is the Chain Rule for derivatives? How do you find the derivative of #y= 6cos(x^2)# ? How do you find the derivative of #y=6 cos(x^3+3)# ? How do you find the derivative of #y=e^(x^2)# ? How do you find the derivative of #y=ln(sin(x))# ? How do you find the derivative of #y=ln(e^x+3)# ? How do you find the derivative of #y=tan(5x)# ? How do you find the derivative of #y= (4x-x^2)^10# ? How do you find the derivative of #y= (x^2+3x+5)^(1/4)# ? How do you find the derivative of #y= ((1+x)/(1-x))^3# ? See all questions in Chain Rule Impact of this question 6164 views around the world You can reuse this answer Creative Commons License