Question

How do you differentiate `f(x)=sinx/(x-3)^3` using the quotient rule?

Answer 1

`y'=(cos(x)(x-3)-3sin(x))/(x-3)^4`

Explanation:

Using the Quotient rule we get

`y'=(cos(x)(x-3)^3-sin(x)3(x-3)^2)/(x-3)^6`
simplifying

`y'=(cos(x)(x-3)-3sin(x))/(x-3)^4`