How do you differentiate f(x)=sqrt(x+1)?

Jul 4, 2016

$= \frac{1}{2 {\left(x + 1\right)}^{\frac{1}{2}}}$

Explanation:

$f \left(x\right) = \sqrt{x + 1}$

$= {\left(x + 1\right)}^{\frac{1}{2}}$

$f ' \left(x\right) = \frac{1}{2} {\left(x + 1\right)}^{- \frac{1}{2}} \cdot 1$

$= \frac{1}{2 {\left(x + 1\right)}^{\frac{1}{2}}}$