Question

How do you differentiate `f(x)=-tansqrt(1/(x^2))` using the chain rule?

Answer 1

`f'(x)=(1+tan^2(sqrt(1/x^2)))/(x^3*sqrt(1/x^2))`

Explanation:

Note that `(tan(x))'=1+tan^2(x)`
then we get by the chain rule

`f'(x)=-(1+tan^2(sqrt(1/x^2)))*1/2*(1/x^2)^(-1/2)*(-2/x^3)`