How do you differentiate #f(x) = x^3(2x-5)^4# using the chain rule? Calculus Basic Differentiation Rules Chain Rule 1 Answer Lucy Apr 11, 2018 #f'(x)=x^2(2x-5)^3(14x-15)# Explanation: #f(x)=x^3(2x-5)^4# #f'(x)=x^3times4(2x-5)^3times2+(2x-5)^4times3x^2# #f'(x)=(2x-5)^3(8x^3+6x^3-15x^2)# #f'(x)=(2x-5)^3(14x^3-15x^2)# #f'(x)=x^2(2x-5)^3(14x-15)# Answer link Related questions What is the Chain Rule for derivatives? How do you find the derivative of #y= 6cos(x^2)# ? How do you find the derivative of #y=6 cos(x^3+3)# ? How do you find the derivative of #y=e^(x^2)# ? How do you find the derivative of #y=ln(sin(x))# ? How do you find the derivative of #y=ln(e^x+3)# ? How do you find the derivative of #y=tan(5x)# ? How do you find the derivative of #y= (4x-x^2)^10# ? How do you find the derivative of #y= (x^2+3x+5)^(1/4)# ? How do you find the derivative of #y= ((1+x)/(1-x))^3# ? See all questions in Chain Rule Impact of this question 1592 views around the world You can reuse this answer Creative Commons License