# How do you differentiate #g(t)=(t-sqrtt)/(t^(1/3))#?

##### 1 Answer

Dec 2, 2016

I would rewrite to avoid the quotient rule.

#### Explanation:

# = t/t^(1/3) - t^(1/2)/t^(1/3)#

# = t^(1-1/3) - t^(1/2-1/3)#

# = t^(2/3) - t^(1/6)#

# = 2/(3root(3)x) - 1/(6 root(6)(x^5))#

If you want a single ratio for the derivative, use

# = (4x-1)/(6root(6)(x^5))#