Question

How do you differentiate `g(x) = (x-7)(x^2+3)` using the product rule?

Answer 1

`3*x^2-14*x+3`

Explanation:

We have`g(x) = (x-7)(x^2+3)`
applying product rule we get

• `dg(x)/dx=(x-7)*dy/dx(x^2+3)+(x^2+3)*dy/dx(x-7)`
• `=>(x-7)*(2*x+0)+(x^2+3)*(1+0)`

using(
`dy/dx=x^n=>n*x^(n-1)`

`dy/dx=k(constant)=>0`)
`=>2*x^2-14*x+x^2+3`

• `=>3*x^2-14*x+3`