How do you differentiate g(x) = (x-7)(x^2+3) using the product rule?
1 Answer
Jun 25, 2018
Explanation:
We have
applying product rule we get
dg(x)/dx=(x-7)*dy/dx(x^2+3)+(x^2+3)*dy/dx(x-7) =>(x-7)*(2*x+0)+(x^2+3)*(1+0)
using(
=>3*x^2-14*x+3