# How do you differentiate g(y) =x^2(x^2 - 1)  using the product rule?

Aug 15, 2017

$g ' \left(x\right) = 4 {x}^{3} - 2 x$
$g \left(x\right) = {x}^{2} \left({x}^{2} - 1\right)$
Differentiating Both sides with respect to $x$ we get
g'(x)=2x (x^2-1)+x^2×2x
$\therefore g ' \left(x\right) = 4 {x}^{3} - 2 x$