How do you differentiate given  12(sin5x)^3?

Jun 13, 2017

$y ' = 120 {\left(\sin 5 x\right)}^{2} \cdot \cos 5 x$

Explanation:

$y ' = 12 \cdot 3 {\left(\sin 5 x\right)}^{2} \cdot \cos 5 x \cdot 5$