Question

How do you differentiate `h(x)=(1-cosx)/sinx` using the quotient rule?

Answer 1

`(1-cosx)/sin^2x`

Explanation:

`h = f/g` Then
`h' = \frac{gf' - fg'}{g^2} = [sin^2x - (1-cosx)cosx]/sin^2 x = (1-cosx)/sin^2x`