# How do you differentiate #h(y)=1/(y^3+2y+1)# using the quotient rule?

##### 1 Answer

Aug 25, 2016

#### Explanation:

The quotient rule states that for some function in the form

Here, for

#{(f(y)=1),(g(y)=y^3+2y+1):}#

We will need to know their derivatives in a moment:

#{(f'(y)=0),(g'(y)=3y^2+2):}#

Plugging these into the quotient rule formula gives us:

#h'(y)=((0)(y^3+2y+1)-(1)(3y^2+2))/(y^3+2y+1)^2#

Simplifying:

#h'(y)=(-3y^2-2)/(y^3+2y+1)^2#