# How do you differentiate implicitly (x^2 + 1)y with respect to x?

You cannot find $\frac{\mathrm{dy}}{\mathrm{dx}}$ without an equation , but here is the derivative of the expression you asked about.
$\frac{d}{\mathrm{dx}} \left(\left({x}^{2} + 1\right) y\right) = \left(2 x\right) y + \left({x}^{2} + 1\right) \frac{\mathrm{dy}}{\mathrm{dx}} = 2 x y + \left({x}^{2} + 1\right) \frac{\mathrm{dy}}{\mathrm{dx}}$