How do you differentiate #lnx^(1/2)#? Calculus Differentiating Exponential Functions Differentiating Exponential Functions with Calculators 1 Answer Michael Mar 6, 2016 You can do it like this: Explanation: #f(x)=lnx^(1/2)# #:.f(x)=(lnx)/(2)# #:.f'(x)=(1/x)/(2)=1/(2x)# Answer link Related questions How do you use a calculator to find the derivative of #f(x)=e^(x^2)# ? How do you use a calculator to find the derivative of #f(x)=e^(1-3x)# ? How do you use a calculator to find the derivative of #f(x)=e^sqrt(x)# ? What is the derivative of #e^(-x)#? What is the derivative of #ln(2x)#? How do you differentiate #(lnx)^(x)#? How do you differentiate #x^lnx#? How do you differentiate #f(x) = e^xlnx#? How do you differentiate #e^(lnx) #? How do you differentiate #y = lnx^2#? See all questions in Differentiating Exponential Functions with Calculators Impact of this question 2233 views around the world You can reuse this answer Creative Commons License