# How do you differentiate log_2 (e)?

${\log}_{a} a = 1$,
${\log}_{e} e = \left({\log}_{2} e\right) \left({\log}_{e} 2\right)$.
So, ${\log}_{2} e = \frac{1}{\log} _ e 2 = \frac{1}{\ln} 2$ = 1.4427, nearly. .