Question

How do you differentiate `log(8x-1)`?

Answer 1

see below

Explanation:

Use the formula below to find the derivative
`color(red)(d/dx(log_bf(x))=1/(f(x)ln b) * f'(x)`

`y=log (8x-1)`

`color(blue)(y'=1/((8x-1)ln10)*8`

`color(blue)(y'=8/((8x-1)ln10)`