How do you differentiate R(t)=5t^(-3/5)R(t)=5t−35?

1 Answer
Jim G.
Dec 5, 2016

R'(t)=-3t^(-8/5)

Explanation:

differentiate using the color(blue)"power rule"

color(orange)"Reminder " color(red)(bar(ul(|color(white)(2/2)color(black)(d/dx(ax^n)=nax^(n-1))color(white)(2/2)|)))

rArrR'(t)=-3/5xx5t^(-3/5-5/5)

=-3t^(-8/5)=-3/(t^(8/5)

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