Question

How do you differentiate `sin(sin(sinx))`?

Answer 1

`(df)/(dx)=cosxcos(sinx)cos(sin(sinx))`

Explanation:

This can be factorized using chain rule for function of a function.

`f(x)=sin(sin(sinx))`

Hence `(df)/(dx)=cos(sin(sinx))xxcos(sinx)xxcosx`

= `cosxcos(sinx)cos(sin(sinx))`