How do you differentiate #tanx+tany=1#?
1 Answer
Feb 20, 2017
# dy/dx = - sec^2x/sec^2y #
Explanation:
When we differentiate
However, we cannot differentiate a non implicit function of
When this is done in situ it is known as implicit differentiation.
We have:
# tanx + tany = 1 #
Differentiate wrt
# sec^2x + sec^2ydy/dx = 0 #
# :. sec^2ydy/dx = - sec^2x #
# :. dy/dx = - sec^2x/sec^2y #