# How do you differentiate #tanx+tany=1#?

##### 1 Answer

Feb 20, 2017

# dy/dx = - sec^2x/sec^2y #

#### Explanation:

When we differentiate

However, we cannot differentiate a non implicit function of

When this is done in situ it is known as implicit differentiation.

We have:

# tanx + tany = 1 #

Differentiate wrt

# sec^2x + sec^2ydy/dx = 0 #

# :. sec^2ydy/dx = - sec^2x #

# :. dy/dx = - sec^2x/sec^2y #