How do you differentiate #V(r)=4/3pir^3#?
1 Answer
Nov 22, 2016
Explanation:
differentiate using the
#color(blue)"power rule"#
#color(orange)"Reminder " color(red)(bar(ul(|color(white)(2/2)color(black)(d/dx(ax^n)=nax^(n-1))color(white)(2/2)|)))#
#rArrV'(r)=3xx4/3pir^2=4pir^2#