Question

How do you differentiate `(x+1)/(x-1)`?

Answer 1

`-2/(x-1)^2`

Explanation:

After the Quotient rule

`(u/v)'=(u'v-uv')/v^2`
we get

`f'(x)=(x-1-(x+1))/(x-1)^2=-2/(x-1)^2`