How do you differentiate x(lnx)^2? Calculus Basic Differentiation Rules Power Rule 1 Answer Himanshu Shekhar Jun 9, 2016 Use the product rule and simplify. d/dx [ x * ln^2(x) ] = ln(x) [ ln(x) +2 ] Explanation: d/dx [ x * ln^2(x) ] = (d/dx [ x ]* ln^2(x)) +( x * d/dx [ ln^2(x) ] ) = (1* ln^2(x)) +( x * d/dx [ ln(x) ] * 2 ln(x)) = ( ln^2(x)) +( x * 1/x * 2 ln(x)) = ( ln^2(x)) +(2 ln(x)) = ln(x) [ ln(x) +2 ] Answer link Related questions How do you find the derivative of a polynomial? How do you find the derivative of y =1/sqrt(x)? How do you find the derivative of y =4/sqrt(x)? How do you find the derivative of y =sqrt(2x)? How do you find the derivative of y =sqrt(3x)? How do you find the derivative of y =sqrt(x)? How do you find the derivative of y =sqrt(x) using the definition of derivative? How do you find the derivative of y =sqrt(3x+1)? How do you find the derivative of y =sqrt(9-x)? How do you find the derivative of y =sqrt(x-1)? See all questions in Power Rule Impact of this question 8840 views around the world You can reuse this answer Creative Commons License