# How do you differentiate x + y^2 = 25?

Jun 27, 2018

$- \frac{1}{2 y}$

#### Explanation:

$\textcolor{b l u e}{\frac{d}{\mathrm{dx}}} \left(x + {y}^{2}\right) = \textcolor{b l u e}{\frac{d}{\mathrm{dx}}} 25$

$1 + 2 y \cdot \frac{\mathrm{dy}}{\mathrm{dx}} = 0$

$2 y \cdot \frac{\mathrm{dy}}{\mathrm{dx}} = - 1$

$\frac{\mathrm{dy}}{\mathrm{dx}} = - \frac{1}{2 y}$