Question

How do you differentiate `y = 2/(e^(x) + e^(-x))`?

Answer 1

In this way, remebering the division rule:

`y'=(0*(e^x+e^-x)-2*(e^x+e^-x*(-1)))/(e^x+e^-x)^2=`

`=(2(e^-x-e^x))/(e^x+e^-x)^2`.