Question

How do you differentiate `y^3-y=x^3-x`?

Answer 1

`y'=(3x^2-1)/(3y^2 -1)`

Explanation:

`(y^3-y=x^3-x)'`
`3y^2 y'-y'=3x^2-1`
`y'(3y^2 -1)=3x^2-1`
`y'=(3x^2-1)/(3y^2 -1)`