Question

How do you differentiate `y =(3x-2)^10` using the chain rule?

Answer 1

`y'=30(3x-2)^9`

Explanation:

According to the chain rule,

`d/dx[u^10]=10u^9*(du)/dx`

Thus,

`y'=10(3x-2)^9*d/dx[3x-2]`

`=>10(3x-2)^9*3`

`=>30(3x-2)^9`