How do you differentiate #y=a^3+cos^3x#?
1 Answer
Jul 17, 2017
Explanation:
#"differentiate using the "color(blue)"chain rule"#
#"given "y=f(g(x))" then"#
#dy/dx=f'(g(x))xxg'(x)larr" chain rule"#
#y=a^3+(cosx)^3#
#rArrdy/dx=0+3(cosx)^2xxd/dx(cosx)#
#color(white)(rArrdy/dx)=-3cos^2xsinx#
