How do you differentiate #y = a / (x - 1) #?
1 Answer
Apr 12, 2017
Explanation:
#"express " y=a/(x-1)=a(x-1)^-1#
#rArrdy/dx=-a(x-1)^-2.d/dx(x-1)larr" chain rule"#
#color(white)(rArrdy/dx)=-a(x-1)^-2=-a/(x-1)^2#
