How do you differentiate y=ax^2+bx+c?

1 Answer
Jim G.
Oct 17, 2016

dy/dx=2ax+b

Explanation:

differentiate using the color(blue)"power rule"

color(red)(bar(ul(|color(white)(a/a)color(black)(d/dx(ax^n)=nax^(n-1))color(white)(a/a)|)))

and color(red)(bar(ul(|color(white)(a/a)color(black)(d/dx("constant")=0)color(white)(a/a)|)))

y=ax^2+bx+clarr" c is a constant"

rArrdy/dx=2ax^(2-1)+bx^(1-1)+0

=2ax^1+bx^0+0=2ax+b

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