How do you differentiate y = cos sec^2(x)?

1 Answer
Apr 13, 2015

(dy)/(dx)=-2sec^2xtanx(sinsec^2(x))
y=(cossec^2(x))

Differentiating both side with respect to 'x'

(dy)/(dx)=d/(dx)(cossec^2(x))

(dy)/(dx)=-sinsec^2(x)d/(dx)(sec^2(x))

(dy)/(dx)=-sinsec^2(x)(2secx)(d/(dx)(secx))

(dy)/(dx)=-sinsec^2(x)(2secx)(secxtanx)

(dy)/(dx)=-sinsec^2(x)(2sec^2xtanx)

(dy)/(dx)=-2sec^2xtanx(sinsec^2(x))